Question:

A 2 m wide truck is moving with a uniform speed v₀ = 8m/s along a straight horizontal road. A pedestrian starts to cross the road with a uniform speed v when the truck is 4 m away from him. The minimum value of v so that he can cross the road safely is 

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For minimum speed, use relative velocity and geometry.
Updated On: Mar 20, 2026
  • \(2.62\,\text{m/s}\)
  • \(4.6\,\text{m/s}\)
  • \(3.57\,\text{m/s}\)
  • 1.414m/s
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The Correct Option is A

Solution and Explanation


Step 1:
Time for truck to reach pedestrian: t = (4)/(8) = 0.5s
Step 2:
Pedestrian must cross 2m in this time: v = (2)/(0.5) = 4m/s Considering diagonal safe path, vmin = 2.62m/s
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