Question:

A boy running on a horizontal road at 8km/h finds rain falling vertically. He increases his speed to 12km/h and finds the drops make 30^∘ with the vertical. The speed of rain with respect to the road is:

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Relative velocity problems often use triangle geometry.
Updated On: Mar 20, 2026
  • \( 4\sqrt{7}\,\text{km/h} \)
  • \( 9\sqrt{7}\,\text{km/h} \)
  • \( 12\sqrt{7}\,\text{km/h} \)
  • 15√(7)km/h
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The Correct Option is A

Solution and Explanation


Step 1:
Initially rain appears vertical ⇒ horizontal component of rain = 8km/h.
Step 2:
When speed becomes 12km/h: tan 30^∘ = (12 - 8)/(v) ⟹ v = 4√(3)
Step 3:
Resultant speed: vᵣ = √(4√(3))² + 8² = 4√(7)km/h
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