\( 25 \, \text{J} \)
\( 50 \, \text{J} \)
To find the kinetic energy of an object, we use the formula for kinetic energy, which is given by:
\[ KE = \frac{1}{2}mv^2 \]
where:
Given that the mass \( m = 0.5 \, \text{kg} \) and the velocity \( v = 10 \, \text{m/s} \), we can substitute these values into the formula:
\[ KE = \frac{1}{2} \times 0.5 \, \text{kg} \times (10 \, \text{m/s})^2 \]
First, calculate the square of the velocity:
\[ (10 \, \text{m/s})^2 = 100 \, \text{m}^2/\text{s}^2 \]
Then, multiply by the mass and divide by 2:
\[ KE = \frac{1}{2} \times 0.5 \times 100 \]
\[ KE = 0.25 \times 100 = 25 \, \text{J} \]
Thus, the kinetic energy of the object is \( \boxed{25 \, \text{J}} \), indicating that there was an error in the provided solution options.
A wall is hit elastically and normally by ‘n’ balls per second. All the balls have the same mass ‘m’ and are moving with the same velocity ‘u’. the force exerted by the balls on the wall is
A 4 kg mass and a 1 kg mass are moving with equal energies. The ratio of the magnitude of their linear momenta is