Question:

\(2\text{MnO}_{2(s)}+2\text{NH}_{4}^{+}+2e^{-}\rightarrow \text{Mn}_{2}\text{O}_{3(s)}+2\text{NH}_{3(aq)}+\text{H}_{2}\text{O}_{(l)}\)
Which of the following cell exhibits above net reduction reaction?

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The reduction of MnO2 with NH4+ ions is the cathode reaction of the dry cell.
Updated On: Nov 12, 2026
  • Leclanche cell
  • \(\text{H}_{2}-\text{O}_{2}\) Fuel cell
  • Lead accumulator
  • NICAD cell
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept
The given half reaction reduces \(\text{MnO}_{2}\) (Mn from +4 to +3) in the presence of \(\text{NH}_{4}^{+}\) ions.

Step 2: Identify the cell
This is the cathode process of the dry cell. It has a zinc can as the anode, a graphite rod with \(\text{MnO}_{2}\) paste as the cathode, and an \(\text{NH}_{4}\text{Cl}\)/\(\text{ZnCl}_{2}\) paste as the electrolyte.

Step 3: Other cells
The hydrogen-oxygen fuel cell, the lead accumulator and the Ni-Cd cell have different electrode reactions and contain no \(\text{MnO}_{2}\).

Final Answer:
The reaction belongs to the Leclanche (dry) cell. \[ \boxed{\text{(A) }\text{Leclanche cell}} \]
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