Question:
\(116g\) \(n\)-butane के पूर्ण दहन पर उत्पन्न कार्बन डाइऑक्साइड की मात्रा है :
(दिया है : atomic mass \(H=1,\; C=12,\; O=16\))
\(116g\) \(n\)-butane के पूर्ण दहन पर उत्पन्न कार्बन डाइऑक्साइड की मात्रा है :
(दिया है : atomic mass \(H=1,\; C=12,\; O=16\))
(दिया है : atomic mass \(H=1,\; C=12,\; O=16\))
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Hydrocarbon combustion में पहले balanced equation लिखना सबसे जरूरी है।
Updated On: Jun 22, 2026
- \(176g\)
- \(362g\)
- \(352g\)
- \(322g\)
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The Correct Option is C
Solution and Explanation
पद 1: प्रश्न को समझना
हमें complete combustion से बनने वाले \(CO_2\) का mass निकालना है।
पद 2: मुख्य सूत्र या दृष्टिकोण
Combustion equation: \[ 2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O \] पद 3: विस्तृत व्याख्या
Molar mass of butane: \[ =4(12)+10(1) \] \[ =58g/mol \] Given: \[ 116g = 2\;mol \] Reaction से: \[ 2\;mol\;C_4H_{10}\rightarrow 8\;mol\;CO_2 \] Thus: \[ CO_2=8mol \] Mass of \(CO_2\): \[ =8\times44 \] \[ =352g \] पद 4: अंतिम उत्तर
अतः सही विकल्प (C) है।
हमें complete combustion से बनने वाले \(CO_2\) का mass निकालना है।
पद 2: मुख्य सूत्र या दृष्टिकोण
Combustion equation: \[ 2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O \] पद 3: विस्तृत व्याख्या
Molar mass of butane: \[ =4(12)+10(1) \] \[ =58g/mol \] Given: \[ 116g = 2\;mol \] Reaction से: \[ 2\;mol\;C_4H_{10}\rightarrow 8\;mol\;CO_2 \] Thus: \[ CO_2=8mol \] Mass of \(CO_2\): \[ =8\times44 \] \[ =352g \] पद 4: अंतिम उत्तर
अतः सही विकल्प (C) है।
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