Question:

0.2 kg ball strikes a wall with velocity \(10\,ms^{-1}\) and rebounds with \(8\,ms^{-1}\). The impulse delivered by the ball is}

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In rebound problems, final velocity must be taken with opposite sign because the direction changes.
Updated On: Apr 24, 2026
  • 0.4 Ns
  • 3.6 Ns
  • 1.4 Ns
  • 1.8 Ns
  • 16.0 Ns
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The Correct Option is B

Solution and Explanation

Impulse is equal to change in momentum: \[ J = m(v_f-v_i) \] Take initial velocity toward the wall as positive: \[ v_i=+10\,ms^{-1} \] After rebound, the direction reverses: \[ v_f=-8\,ms^{-1} \] So, \[ J=0.2(-8-10) \] \[ J=0.2(-18)=-3.6 \text{ Ns} \] Magnitude of impulse: \[ |J|=3.6\text{ Ns} \]
Hence, the correct answer is: \[ \boxed{(B)\ 3.6\text{ Ns}} \]
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