Impulse is equal to change in momentum:
\[
J = m(v_f-v_i)
\]
Take initial velocity toward the wall as positive:
\[
v_i=+10\,ms^{-1}
\]
After rebound, the direction reverses:
\[
v_f=-8\,ms^{-1}
\]
So,
\[
J=0.2(-8-10)
\]
\[
J=0.2(-18)=-3.6 \text{ Ns}
\]
Magnitude of impulse:
\[
|J|=3.6\text{ Ns}
\]
Hence, the correct answer is:
\[
\boxed{(B)\ 3.6\text{ Ns}}
\]