Motion of a particle is given by equation \(S=(3t^3+7t^2+14t+8)\ m\), The value of acceleration of the particle at \(t=1 \ sec\) is:
A charge having \(q/m\) equal to \(10^8 \ c/kg\) and with velocity \(3×10^5 \ m/s \) enters into a uniform magnetic field \(B=0.3 \ tesla\) at an angle \(30º\) with direction of field. Then radius of curvature will be:
Two stationary sources each emitting waves of wave length \(λ\). An observer moves from one source to other with velocity \(u\). Then number of beats heard by him:
The equations of two waves given as \(x=acos\ (ωt + δ)\) and \(y=a cos\ (ωt+α)\), Where \(δ=α+\frac \pi 2\), then resultant wave represent:
For the given reaction, the particle X is: 6C11→5B11+β++X