For the reaction \(A(g) \rightleftharpoons B(g)\) at 495 K, \(\Delta_rG^\circ = -9.478\) kJ mol\(^{-1}\).
If we start the reaction in a closed container at 495 K with 22 millimoles of A, the amount of B in the equilibrium mixture is ____________ millimoles.
(Round off to the Nearest Integer). [R = 8.314 J mol\(^{-1}\) K\(^{-1}\); ln 10 = 2.303]