Given :
\(E^\circ_{\frac{1}{2}\mathrm{Cl_2/Cl^-}} = 1.36\ \mathrm{V},\ E^\circ_{\mathrm{Cr^{3+}/Cr}} = -0.74\ \mathrm{V}\)
\(E^\circ_{\mathrm{Cr_2O_7^{2-}/Cr^{3+}}} = 1.33\ \mathrm{V},\ E^\circ_{\mathrm{MnO_4^-/Mn^{2+}}} = 1.51\ \mathrm{V}\)
The correct order of reducing power of the species \((\mathrm{Cr, Cr^{3+}, Mn^{2+}}\) and \(\mathrm{Cl^-})\) will be :