What is the pH of a \(10^{-4}\ \mathrm{M\ OH^-}\) solution at 330 K, if \(K_w\) at 330 K is \(10^{-13.6}\) ?
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- 4
- 9.0
- 10
- 9.6
The Correct Option is D
Solution and Explanation
\([H^+] = \frac{K_w}{[OH^-]} = \frac{10^{-13.6}}{10^{-4}} = 10^{-9.6}\) M.
\(\mathrm{pH} = -\log[H^+] = 9.6\).
(Do not use pH = 14 - pOH = 10, because \(pK_w = 13.6\) here, not 14.)
Answer: (4) 9.6
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