Question:

Identify incorrect statement :

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Copper(I) is \(d^{10}\), so its compounds are normally colourless and diamagnetic, but \(\mathrm{Cu_2O}\) and \(\mathrm{Cu_2S}\) have specific well-known colours.
Updated On: Oct 31, 2026
  • \(\mathrm{Cu_2O}\) is colourless.
  • Copper (I) compounds are colourless except when colour results from charge transfer.
  • Copper (I) compounds are diamagnetic.
  • \(\mathrm{Cu_2S}\) is black.
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The Correct Option is A

Solution and Explanation

\(\mathrm{Cu^+}\) has the configuration \(3d^{10}\): no unpaired electrons, so Cu(I) compounds are diamagnetic (statement 3 correct) and, as there are no d-d transitions, colourless unless colour arises from charge transfer (statement 2 correct).
\(\mathrm{Cu_2S}\) is a black solid (statement 4 correct).
\(\mathrm{Cu_2O}\) is a red solid (the colour arises from charge transfer), so saying it is colourless is wrong.
Hence statement (1) is incorrect.
Answer: (1) \(\mathrm{Cu_2O}\) is colourless.
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