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JEE Main
List of top Questions asked in JEE Main
Two points (5, 2) and (2, a). Line passes through these points makes an angle of π/4 at origin. The product of all values of a is equal to
JEE Main
Mathematics
Lines and Angles
A triangle is drawn inside a bounded region of y
2
= 2x and x = 24. Then maximum area of triangle is
JEE Main
Mathematics
Triangles
If |x + 1||x + 3| – 4|x + 2| + 5 = 0, then sum of squares of solutions is
JEE Main
Mathematics
General and Particular Solutions of a Differential Equation
If solution of differential equation xdy - ydx = xy(xdy - ydx) and y(1) = 1 is α|y| = |x|e
(xy - β)
then (α + β) is equal to
JEE Main
Mathematics
Derivatives
If the complex number (1 + 2i cosθ) / (1 - 3i cosθ) is purely imaginary, then find the number of values of θ in the interval [-2π, 2π].
JEE Main
Mathematics
Complex numbers
Given
\(f(x) = \begin{cases} \frac{tan((a+1)x)+tanx\cdot b}{x} & \quad x\lt 0\\ 3 & \quad x=0\\ \frac{\sqrt{ax+b^2x^2}-\sqrt{ax}}{\sqrt{a}bx\sqrt{x}} & \quad x\gt 0\end{cases}\)
It is a continuous function at x=0, then find
\(\frac{b}{a}\)
JEE Main
Mathematics
Continuity and differentiability
Molecular orbital σ* represents:
JEE Main
Chemistry
Molecular Orbital Theory
Velocity of a particle of mass m as a function of displacement x is given by v = ɑ√x. Work done to move it from x = 0 to x = d is:
JEE Main
Physics
Work-energy theorem
Two persons are pulling a rope towards themselves with a force of 200 N each. If the Young's modulus is 2 x 10
11
N/m
2
and area of cross-section is 2 cm
2
for the rope, the elongation in the rope is ____.
(distance between the persons holding the ropes is 2 m.)
JEE Main
Physics
Hooke's Law
Assertion (A): Object at radius of curvature of biconvex lens made by glass (u = 1.5) form image at same distance an other side of the lens.
Reason (R): Image of a real object formed by concave lens is always virtual and erect.
JEE Main
Physics
Ray optics and optical instruments
Find the equivalent resistance between terminal A and B for the given network.
JEE Main
Physics
Resistance
Consider the following electronic configuration:
Cu
2+
= [Ar] 3d
4
4s
0
Cu
+
= [Ar] 3d
10
4s
0
Which option is correct?
JEE Main
Chemistry
Electronic Configurations Of Elements And The Periodic Table
Consider the following compound.
Correct order of their basicity is:
JEE Main
Chemistry
Acids and Bases
Which of the following is colorless?
JEE Main
Chemistry
properties of d block elements
Which among the following have a single unpaired electron?
N
2
, 0
2
, CN
-
, O
2
-
, C
2
2-
, N
2-
JEE Main
Chemistry
Mole concept and Molar Masses
S-I: Sulphur exists as S8 while oxygen exists as O2.
S-II: In oxygen, pπ-pπ bonding occurs while it is not effective in sulphur.
JEE Main
Chemistry
Chemical bonding and molecular structure
Consider the reaction between PbS and HNO
3
.
PbS + HNO
3
→
Which of the following is not formed.
JEE Main
Chemistry
Redox reactions
A ray of light passing through (1, 2) after reflecting on x-axis at point Q passes through R(3, 4). If S(h, k) is such that PQRS is a parallelogram, then find the value of hk
2
.
JEE Main
Mathematics
Coordinate Geometry
A, B and C are given as
A = αî + 4j + 5k
B = 2î + 5j + 6k
C=A+B
|C| = | A - B |
Find the value of α and |C|
2
is:
JEE Main
Mathematics
Vector Algebra
If set A = { z: |z - 1| ≤ 1} and set B = { z: |z - 5i| ≤ |z - 5| }, if z = a + ib, where a, b ∈ I, then find the sum of modulus squares of A ∩ B.
JEE Main
Mathematics
Complex numbers
What will be the remainder when (428)
2024
is divided by 21?
JEE Main
Mathematics
Number Systems
If A is 3 x 3 matrix, det(3adj (2 adj A)) = 2
-13
.
3
-10
and det(3adj (2A)) = 2
-m.
3
-n
, then find 2m + 2n.d by 21?
JEE Main
Mathematics
Determinants
If f(x) = 3ax
3
+ bx
2
+ cx + 1 and f(1) = 41, f'(1) = 2 and f''(2)= 4, then find (a
2
+ b
2
+ c
2
).
JEE Main
Mathematics
Functions
If the domain of
\(f(x)=\sin^{-1}(\frac{x-1}{2x+3})\)
is R – (α, β] then find the value of 12αβ.
JEE Main
Mathematics
Inverse Trigonometric Functions
A = {2,4,6,8}, B = {3,7,6,9}. R: A × B → A × B such that (a
1
, b
1
) R (a
2
, b
2
) ⇔ a
1
+ a
2
= b
1
+ b
2
where (a
1
, b
1
) ∈ A, (a
2
, b
2
) ∈ B. Find the number of elements in the relation.2)= 4, then find (a
2
+ b
2
+ c
2
).
JEE Main
Mathematics
Relations and functions
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