If a point $P (\alpha, \beta, \gamma)$ satisfying $(\alpha\,\, \beta\,\, \gamma) \begin{pmatrix} 2 & 10 & 8 \\9 & 3 & 8 \\8 & 4 & 8\end{pmatrix}=(0\,\,0\,\,0) $ lies on the plane $2 x+4 y+3 z=5$, then $6 \alpha+9 \beta+7 \gamma$ is equal to :
Let P = \(\left[\begin{matrix} \frac{\sqrt3}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt3}{2} \end{matrix}\right]\) A = \(\left[\begin{matrix} 1 & 1 \\ 0 & 1 \end{matrix}\right]\) and Q = PAPT. If PTQ2007P = \(\left[\begin{matrix} a & b \\ c & d \end{matrix}\right]\), then 2a+b-3c-4d equal to
Let\( S={x∈R:0<x<1 and\ 2 tan−1\frac{(1+x)}{(1−x)}=cos^{−1}\frac{(1-x^2)}{(1+x^2)}}\). If n(S) denotes the number of elements in S then :
For the system of linear equations \(x+y+z=6\) \(\alpha x+\beta y+7 z=3\) \(x+2 y+3 z=14\). which of the following is NOT true ?
Among the relations $S=\left\{(a, b): a, b \in R -\{0\}, 2+\frac{a}{b}>\right\}$ and $T=\left\{(a, b): a, b \in R , a^2-b^2 \in Z\right\}$,