\(\exp\left(\frac{\pi - 4}{4\sqrt{2}}\right)\)
\(\exp\left(\frac{4 - \pi}{4\sqrt{2}}\right) \)
\(\exp\left(\frac{1 - \pi}{4\sqrt{2}}\right)\)
\(\exp\left(\frac{4 + \pi}{4\sqrt{2}}\right)\)
The given differential equation is:
\[ \frac{dy}{dx} - \frac{3x^5 \tan^{-1}(x^3)}{(1 + x^6)^{3/2}} y = 2x. \]
The integrating factor (I.F.) is given by:
\[ \text{I.F.} = e^{\int -\frac{3x^5 \tan^{-1}(x^3)}{(1 + x^6)^{3/2}} dx}. \]
The integral simplifies as:
\[ \int -\frac{3x^5 \tan^{-1}(x^3)}{(1 + x^6)^{3/2}} dx = \tan^{-1}(x^3) \cdot \frac{x^3}{\sqrt{1 + x^6}}. \]
Thus, the integrating factor becomes:
\[ \text{I.F.} = e^{\tan^{-1}(x^3) \cdot \frac{x^3}{\sqrt{1 + x^6}}}. \]
The general solution of the differential equation is:
\[ y \cdot \text{I.F.} = \int 2x \cdot \text{I.F.} dx + C. \]
Substitute the I.F.:
\[ y \cdot e^{\tan^{-1}(x^3) \cdot \frac{x^3}{\sqrt{1 + x^6}}} = \int 2x dx + C. \]
Simplify:
\[ y \cdot e^{\tan^{-1}(x^3) \cdot \frac{x^3}{\sqrt{1 + x^6}}} = x^2 + C. \]
At \(x = 0\), \(y = 0\). Substitute:
\[ 0 \cdot e^{\tan^{-1}(0) \cdot 0 \cdot \sqrt{1 + 0^6}} = 0^2 + C \implies C = 0. \]
Thus, the solution becomes:
\[ y \cdot e^{\tan^{-1}(x^3) \cdot \frac{x^3}{\sqrt{1 + x^6}}} = x^2. \]
At \(x = 1\):
\[ y(1) \cdot e^{\tan^{-1}(1^3) \cdot \frac{1^3}{\sqrt{1 + 1^6}}} = 1^2. \]
Simplify the terms:
\[ y(1) \cdot e^{\frac{\pi}{4} \cdot \frac{1}{\sqrt{2}}} = 1. \]
Rewriting the exponent:
\[ y(1) = e^{-\frac{\pi}{4\sqrt{2}}}. \]
Express the exponent further:
\[ y(1) = \exp\left(\frac{4 - \pi}{4\sqrt{2}}\right). \]
The value of \(y(1)\) is:
\[ \boxed{\exp\left(\frac{4 - \pi}{4\sqrt{2}}\right)}. \]
Therefore, the correct answer is (B).
Let $y=y(x)$ be the solution of the differential equation $\left(x^2-3 y^2\right) d x+3 x y d y=0, y(1)=1$.Then $6 y^2( e )$ is equal to
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,