List of practice Questions

Against which law was a meeting organised in Jallianwala Bagh?
When was the unification of Italy completed?
Louis Philippe was the ruler of which country?
In which year was the International Women's Day announced?
The Parliament of Russia is called
Where was the Communist Party of India established?
Where was Tonkin free school established?
During whose reign was the Ilbert bill passed?
In which Congress session was the proposal of non-cooperation movement adopted?
In which country did printing start?
If \( p(x) = x^4 - 5x + 6 \) and \( q(x) = 2 - x^2 \), then the degree of \( \frac{p(x)}{q(x)} \) is:
If \( \tan(\alpha + \beta) = \sqrt{3} \) and \( \tan \alpha = \frac{1}{\sqrt{3}} \), then the value of \( \tan \beta \) is:
Evaluate \( \frac{\sec(90^\circ - \theta) \csc\theta - \tan(90^\circ - \theta) \cot\theta + \cos^2 25^\circ + \cos^2 65^\circ}{3\tan 27^\circ \tan 63^\circ} \).
If \( \alpha \) and \( \beta \) are the roots of the quadratic equation \( x^2 - 8x + 5 = 0 \), then the value of \( \alpha^2 + \beta^2 \) is:
If \( p(y) = (y+1)(y^3+2)(y^4+6) \) and \( g(y) = y^2 - 3y +1 \), then the degree of \( \frac{p(y)}{g(y)} \) is:

Which of the following is not an A.P.?

If \( \tan(\alpha + \beta) = \sqrt{3} \) and \( \tan \alpha = \frac{1}{\sqrt{3}} \), then the value of \( \tan \beta \) is
If \( p(x) = x^4 - 5x + 6 \) and \( q(x) = 2 - x^2 \), then the degree of \( \frac{p(x)}{q(x)} \) is:
If \( p(y) = (y + 1)(y^3 + 2)(y^4 + 6) \) and \( g(y) = y^2 - 3y + 1 \), then the degree of \( \frac{p(y)}{g(y)} \) is:
In \( \triangle ABC \), \( AD \) is the bisector of \( \angle BAC \). If \( AB = 4 \, \text{cm} \), \( AC = 6 \, \text{cm} \), and \( BD = 2 \, \text{cm} \), then the value of \( DC \) is:
In triangle \( ABC \), \( DE \parallel BC \) such that
\[ \frac{AD}{DB} = \frac{4}{x - 4} \quad \text{and} \quad \frac{AE}{EC} = \frac{8}{3x - 19}, \] then the value of \( x \) is:
If in \( \triangle ABC \), \( AB = 13 \, \text{cm} \), \( BC = 12 \, \text{cm} \), and the value of \( \angle C \) is:
If the ratio of areas of two equilateral triangles is 9:4, then the ratio of their perimeters is:
In \( \triangle ABC \) and \( \triangle DEF \), \( \frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF} = \frac{5}{7} \), then the ratio of the areas of \( \triangle ABC \) and \( \triangle DEF \) is:
In \( \triangle ABC \) and \( \triangle PQR \), the area of \( \triangle ABC \) is to the area of \( \triangle PQR \) as \( 49:16 \), then the ratio of their corresponding sides is: