We can apply the cosine rule to find the angle \( C \):
\[
\cos C = \frac{AB^2 + BC^2 - AC^2}{2 \cdot AB \cdot BC}.
\]
We are given that \( AB = 13 \, \text{cm} \), \( BC = 12 \, \text{cm} \), and using the Pythagorean theorem, \( AC = \sqrt{13^2 - 12^2} = 5 \, \text{cm} \). Substituting the values:
\[
\cos C = \frac{13^2 + 12^2 - 5^2}{2 \cdot 13 \cdot 12} = \frac{169 + 144 - 25}{2 \cdot 13 \cdot 12} = \frac{288}{312} = 0.923.
\]
Thus, \( \angle C = \cos^{-1}(0.923) = 60^\circ \).
Thus, the correct answer is \( \boxed{60^\circ} \).