For two similar triangles, the ratio of their areas is the square of the ratio of their corresponding sides. Since \( \frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF} = \frac{5}{7} \), the ratio of the areas is:
\[
\frac{\text{Area of } \triangle ABC}{\text{Area of } \triangle DEF} = \left( \frac{5}{7} \right)^2 = \frac{25}{49}.
\]
Thus, the correct answer is \( \boxed{25:49} \).