List of top Chemistry Questions

Assertion (A): Enantiomers are inseparable on simple column chromatography. Reason (R): Enantiomers bind achiral stationary phase with equal affinity and Enantiomers can be separated by using chiral stationary phase.

Assertion (A): HBr addition to alkenes gives Markonikov addition. Reason (R): HBr addition to alkene in the presence of peroxide gives Anti-Markonikov addition as the reaction proceeds via radical mechanism.

Assertion (A): Carbon halogen bond in aryl and vinyl halides are unusually shorter. Reason (R): Chlorobenzene and vinyl chlorides undergo $S_N1$ and $S_N2$ reaction in general.

Relative rate of alkaline hydrolysis of the following compound: 4-R-ethyl benzoate where R is: (A) $NO_2$, (B) $Cl$, (C) $H$, (D) $CH_3$, (E) $OCH_3$

Assertion (A): In $S_N1$ reaction racemic mixture is formed and in $S_N2$ reaction inversion of configuration is observed. Reason (R): $S_N1$ reaction is concerted mechanism and $S_N2$ reaction involves carbocation intermediate.

The Interhalogen compound used in the estimation of iodine number in fats and oils is:

IUPAC name of the following compound is:

Find the product X, Y in the following reaction:

Natural Mechanism in human body to inhibit the heavy metal ion poisoning is by:

What type of bonding is present in clathrate compounds?

Using the Pourbaix Diagram for Iron, choose the Incorrect statement:

Which of the following organometallic complex do NOT OBEY 18 EAN Rule?

The Radial wave function for 2p orbital is:

In metal carbonyl, IR absorption can distinguish nature of CO because:

For Schrodinger Wave Equation $\nabla^{2}\psi+\frac{8\pi^{2}m}{h^{2}}(E-V)\psi=0$, an acceptable solution does NOT possess which of the following property?}

The element with highest Electron Affinity among Group 16 is:

Match List - I (Compounds) with List - II (Applications): (A) Silicones, (B) Boranzines, (C) Phosphazenes, (D) Poly siloxanes

Assertion (A): He and Ne do not form clathrates. Reason (R): He and Ne can be separated from Ar, Kr and Xe using quinol from the mixture of these gas.

Match List - I (Compounds) with List - II (Hybridization and no. of L.P.): (A) $SF_{4}$, (B) $ClF_{3}$, (C) $H_{2}O$, (D) $NH_{3}$}

Match List - I (Compounds) with List - II (Geometry): (A) $XeF_{2}$, (B) $XeF_{4}$, (C) $XeF_{6}$, (D) $XeO_{3}$}

Assertion (A): In $B_{2}H_{6}$, two bridging H atoms prevent the rotation between B atoms. Reason (R): Terminal B-H bonds are normal covalent bonds i.e. two centre two electron ($2C-2e$) bonds.}

Assertion (A): In $[Ti(H_{2}O)_{6}]^{3+}$ electronic spectra the observed absorption is unsymmetrical appears to be result of more than one absorption bands. Reason (R): Due to Jahn Teller effect energy of $d_{xy}$ is lowered so shown electronic jump $d_{xy}^{1} \rightarrow d_{x^{2}-y^{2}}$ and $d_{xy}^{1} \rightarrow d_{z^{2}}$ so give rise two absorption bands.}

Arrange the following ligands as per increasing hepticity: A. Allyl, B. Butadiene, C. Phenyl, D. Tropillium, E. Cyclooctatriene.

Arrange the following in increasing order of spin only magnetic movement: (A) $Co^{2+}$, (B) $Ti^{3+}$, (C) $Ti^{2+}$, (D) $Fe^{2+}$, (E) $Sc^{3+}$}

Assertion (A): $Na^{+}(C_{5}H_{11})^{-}$ is more stable than $Na^{+}(C_{5}H_{5})^{-}$. Reason (R): $C_{5}H_{5}$ readily accept electron to become 6-electron aromatic $C_{5}H_{5}^{-}$.}