List of top Questions asked in AP EAPCET- 2023

What are X and Y respectively in the following reaction? $$ CH_3CH_2CHO + 2Cu^{2+} + 5OH^- \rightarrow X + Y + 3H_2O $$

Given below are two statements Assertion (A): The enthalpy of formation of graphite is taken as zero. Reason (R): Graphite is thermodynamically most stable allotrope of carbon. The correct answer is

Evaluate the integral: \[ \int \frac{dx}{4 + 5 \cos x} \]

If $ a = 2n $ and $ b = 2m+1 $ for all $ m, n \in \mathbb{N} $, then \[ \int_{-\pi}^{\pi} e^{\sin^2 x} \cot^{b}(2n+1) x \, dx = \]

If \((l_1, m_1, n_1), (l_2, m_2, n_2)\) are the direction cosines of two lines, then \[ (l_2m_1 - l_1m_2)^2 + (m_1n_2 - m_2n_1)^2 + (n_1l_2 - n_2l_1)^2 + (l_1l_2 + m_1m_2 + n_1n_2)^2 = \]

500 mL of 0.1M HCl is mixed with 500 mL of 0.02M HA (weak acid) solution. To this solution, 2 g of solid NaOH is added. What is the pH of the resultant solution? (Given} \( K_a \) of HA is \( 4 \times 10^{-10} \), molar mass of NaOH is 40 g/mol, log 2 = 0.3, log 4 = 0.6\bf{)

Observe the following half cell reactions and choose the correct options
(I) 2H2O(l) → O2(g)+4H+ +4e− E0 = 1.23V
(II) H+(aq) + e− → 1/2 H2(g) E0 = 0.00V
(III) 2SO4^2− (aq) → S2O8^2− (aq)+2e− E0 = −1.96V
(a) In dilute H2SO4 solution, H+ ions are reduced at cathode.
(b) In concentrated H2SO4 solution, water is oxidized at anode.
(c) In dilute H2SO4 solution, water is oxidized at anode.
(d) In dilute H2SO4 solution, SO4^2− ions are oxidized at anode.

Let \( B = \begin{bmatrix} 2 & 6 & 4 \\ 1 & 0 & 1 \\ -1 & -1 & -1 \end{bmatrix} \), \( C = \begin{bmatrix} -1 & 0 & 1 \\ 1 & 1 & 3 \\ 2 & 0 & 2 \end{bmatrix} \), and if a matrix \( A \) is such that \( BAC = I \), then \( A^{-1} = \)

Which of the following represents the roasting of the ore?

The O-H bond length in \( H_2O \) in gas phase is

If \( f(x) = \frac{x^3 + 5}{\sqrt{12 + x}} \) and } \[ \int_{-5}^{5}f(x) \, dx = \int_{0}^{5} \left( f(x) + g(x) \right) \, dx, \text{ then } g(x) = \]

If \[ \int \frac{x^3}{\sqrt{1 + x^2}} \, dx = A(1 + x^2)^{\frac{3}{2}} + B(1 + x^2)^{\frac{1}{2}} + C, \text{ then } A + B = \]

A reverse biased zener diode when operated in the breakdown region works as

Let \( f(x) = |x| \) and \( g(x) = |x| + a \), \( (a>0) \). For \( 0 \le x \le b \), \( \{(x, y) / g(x) \le y \le f(x)\} \) represents all the points in the interior of

Evaluate the integral: \[ \int_0^1 \left( \sqrt{10} \right)^{2x} \, dx \]

Evaluate: \[ \frac{1}{\cos 290^\circ} + \frac{1}{\sqrt{3} \sin 250^\circ} \]