Xenon (VI) fluoride on complete hydrolysis gives an oxide of xenon 'O'. The total number of \( \sigma \) and \( \pi \) bonds in 'O' is:
Step 1: Understanding the Hydrolysis of Xenon (VI) Fluoride
- \( XeF_6 \) undergoes complete hydrolysis to form Xenon trioxide (\( XeO_3 \)): \[ XeF_6 + 3H_2O \rightarrow XeO_3 + 6HF \] - The molecular structure of \( XeO_3 \) is trigonal pyramidal.
Step 2: Counting \( \sigma \) and \( \pi \) Bonds
- Each Xe–O bond contains one \( \sigma \)-bond.
- Each O has one \( \pi \)-bond with Xe.
- Total bonds: \( 3\sigma + 3\pi = 6 \) bonds.
| Molisch's lest | Barfoed Test | Biuret Test | |
|---|---|---|---|
| A | Positive | Negative | Negativde |
| B | Positive | Positive | Negative |
| C | Negative | Negative | Positive |
According to MO theory, the molecule which contain only π-Bonds between the atoms is
In which if the following changes there is no change in hybridization of the central atom?
For the reaction at 25° C, X2O4 (l) → 2XO2(g), U and S are 2.1 K.Cal and 20 Cal/K respectively. what is G for the reaction at the same temperature? (R = 2 CAL K-1MOL-1)
The hybrids of which group elements of the periodic table form electron precise hybrids?