Question:

\(X\) is the product obtained by hydrolysis of prop-1-yne in the presence of mercuric sulphate under dilute acidic medium. \(Y\) is obtained by the reaction of ethanenitrile with methyl magnesium bromide in dry ether followed by hydrolysis. IUPAC name of product obtained from \(X\) and \(Y\) in presence of barium hydroxide followed by heating is :

Updated On: Apr 12, 2026
  • 2-Methylpent-4-en-3-one
  • 4-Methylpent-3-en-2-one
  • 4-Methylpent-1-ene
  • 2-Methylpent-3-one
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The Correct Option is B

Solution and Explanation

Concept: Terminal alkynes undergo hydration (HgSO\(_4\)/H\(_2\)SO\(_4\)) giving ketones via keto–enol tautomerism. Step 1: {Find product \(X\)} \[ CH_3-C\equiv CH \] Hydration gives: \[ CH_3COCH_3 \] Thus \(X =\) acetone (propanone). Step 2: {Find product \(Y\)} \[ CH_3CN + CH_3MgBr \] After hydrolysis: \[ CH_3COCH_3 \] Thus \(Y =\) acetone. Step 3: {Reaction between \(X\) and \(Y\)} Two acetone molecules undergo aldol condensation in presence of \(Ba(OH)_2\). Intermediate: \[ \text{diacetone alcohol} \] On heating (dehydration): \[ \text{mesityl oxide} \] IUPAC name: \[ 4\text{-Methylpent-3-en-2-one} \]
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