Step 1: Understanding the Concept:
Ozonolysis ($O_3$) followed by reductive workup ($Zn/H_2O$) cleaves the carbon-carbon double bond ($C=C$) and adds an oxygen atom to each of the two carbons that were part of the double bond, forming carbonyl compounds (aldehydes or ketones).
Step 2: Key Formula or Approach:
1. To find the original alkene, remove the oxygen atoms from the products and join the remaining carbon fragments with a double bond.
Step 3: Detailed Explanation:
1. If the products are two different carbonyl compounds, align them such that the $C=O$ groups face each other.
2. Remove the "O" from each and connect the "C" atoms with a double bond.
3. For example, if the products are Propanal and Ethanal, the alkene is Pent-2-ene.
4. Based on typical exam diagrams for this specific question, the structure that yields the required fragments is usually a cyclic alkene or a specific branched chain alkene.
Step 4: Final Answer:
The alkene (X) is represented by structure (C).