Step 1:\( \left(x^k + \dfrac{1}{x^k}\right)^2 = x^{2k} + 2 + \dfrac{1}{x^{2k}} \) Step 2:\( \sum_{k=1}^{n} \left( x^{2k} + x^{-2k} \right) + 2n \) Step 3:Evaluating geometric sums gives option (A).