Question:

X and Y in the below reaction are ----------- and ------------, respectively.

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Acid chloride + H$_2$/Pd-BaSO$_4$ → Aldehyde (Rosenmund reduction)
Updated On: May 1, 2026
  • SOCl$_2$ and C$_6$H$_5$CHO
  • (COCl)$_2$ and C$_6$H$_5$CH$_3$
  • SOCl$_2$ and C$_6$H$_5$CH$_3$
  • (COCl)$_2$ and C$_6$H$_5$CH$_2$OH
  • SOCl$_2$ and C$_6$H$_5$CH$_2$Cl
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The Correct Option is A

Solution and Explanation


Concept:

• Carboxylic acids react with SOCl$_2$ to form acid chlorides.
• Acid chlorides undergo Rosenmund reduction to form aldehydes.

Step 1: Formation of acid chloride

\[ C_6H_5COOH + SOCl_2 \rightarrow C_6H_5COCl + SO_2 + HCl \] Thus, X = SOCl$_2$

Step 2: Rosenmund reduction

\[ C_6H_5COCl \xrightarrow{H_2/Pd/BaSO_4} C_6H_5CHO \] Thus, Y = benzaldehyde Final Conclusion: \[ \boxed{(A)} \]
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