Question:

Which statement best represents Kirchhoff's Law of Thermal Radiation?

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Remember Kirchhoff's Law: \[ \boxed{\varepsilon=\alpha} \] Good absorbers are also good emitters.
Updated On: Jul 24, 2026
  • Good absorbers are poor emitters of radiation
  • All bodies emit radiation equally regardless of material
  • Radiation intensity depends only on temperature
  • Emissivity of a body equals its absorptivity at thermal equilibrium
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The Correct Option is D

Solution and Explanation

Concept: Kirchhoff's Law of Thermal Radiation states that for a body in thermal equilibrium, the emissivity is equal to the absorptivity at the same wavelength and temperature.

Step 1:
State the law. \[ \boxed{\varepsilon=\alpha} \] where
• \(\varepsilon\) = emissivity
• \(\alpha\) = absorptivity

Step 2:
Identify the correct statement. Therefore, \[ \boxed{\text{Emissivity equals absorptivity at thermal equilibrium}.} \] Hence, the correct option is \[ \boxed{(D).} \]
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