Question:
Which one of the following molecules is formed by \(sp^3d^2\) hybridisation?
Which one of the following molecules is formed by \(sp^3d^2\) hybridisation?
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Octahedral geometry may involve either \(d^2sp^3\) or \(sp^3d^2\), depending on inner or outer orbital participation.
Updated On: Apr 29, 2026
- \(BrF_5\)
- \(PF_5\)
- \(SF_6\)
- \([Co(NH_3)_6]^{3+}\)
- \([PtCl_6]^{2-}\)
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The Correct Option is
Solution and Explanation
\(sp^3d^2\) hybridisation corresponds to octahedral geometry.
Among the options, \([PtCl_6]^{2-}\) is the standard complex associated with outer orbital octahedral \(sp^3d^2\) hybridisation.
Hence,
\[
\boxed{(E)\ [PtCl_6]^{2-}}
\]
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