Question:
Which one of the following molecule/ion has square planar shape
Which one of the following molecule/ion has square planar shape
Show Hint
For square planar geometry, look for molecules with a central atom having 6 electron pairs (like XeF\(_4\), ICl\(_4^-\)).
Updated On: Apr 24, 2026
- SF\(_4\)
- NH\(_4^+\)
- CH\(_2\)Cl\(_2\)
- CH\(_4\)
- XeF\(_4\)
Show Solution
Verified By Collegedunia
The Correct Option is
Solution and Explanation
Step 1: Understanding the Concept:
The shape of a molecule is determined by the Valence Shell Electron Pair Repulsion (VSEPR) theory, which considers both bond pairs and lone pairs of electrons around the central atom.
Step 2: Detailed Explanation:
Analyze the shape of each species:
• SF\(_4\): Central S has 5 electron pairs (4 bond pairs, 1 lone pair). Shape is see-saw.
• NH\(_4^+\): Central N has 4 bond pairs, no lone pairs. Shape is tetrahedral.
• CH\(_2\)Cl\(_2\): Central C has 4 bond pairs. Shape is tetrahedral.
• CH\(_4\): Central C has 4 bond pairs. Shape is tetrahedral.
• XeF\(_4\): Central Xe has 6 electron pairs (4 bond pairs, 2 lone pairs). The two lone pairs occupy opposite positions, giving a square planar shape.
Step 3: Final Answer:
XeF\(_4\) has a square planar shape.
The shape of a molecule is determined by the Valence Shell Electron Pair Repulsion (VSEPR) theory, which considers both bond pairs and lone pairs of electrons around the central atom.
Step 2: Detailed Explanation:
Analyze the shape of each species:
• SF\(_4\): Central S has 5 electron pairs (4 bond pairs, 1 lone pair). Shape is see-saw.
• NH\(_4^+\): Central N has 4 bond pairs, no lone pairs. Shape is tetrahedral.
• CH\(_2\)Cl\(_2\): Central C has 4 bond pairs. Shape is tetrahedral.
• CH\(_4\): Central C has 4 bond pairs. Shape is tetrahedral.
• XeF\(_4\): Central Xe has 6 electron pairs (4 bond pairs, 2 lone pairs). The two lone pairs occupy opposite positions, giving a square planar shape.
Step 3: Final Answer:
XeF\(_4\) has a square planar shape.
Was this answer helpful?
0
0
Top KEAM Chemistry Questions
- The pH of a solution obtained by mixing 60 mL of 0.1 M BaOH solution at 40m of 0.15m HCI solution is
- $4\, g$ of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave $5\, g$ of its oxide. The equivalent weight of copper is :
- Green chemistry deals with
- Neopentyl bromide undergoes dehydrohalogenation to give alkenes even though it has no $\beta$- hydrogen. This is due to
- Plot of $ log\text{ }x/m $ against log $p$ is a straight line inclined at an angle of $ 45{}^\circ $ . When the pressure is $ 0.5 \,arm $ and Freundlich parameter. $ k $ is $ 10 $ , the amount of solute adsorbed per gram of adsorbent will be $ (log\text{ }5=0.6990) $
View More Questions
Top KEAM Molecular Geometry Questions
- The correct increasing order of dipole moment of \( NF_3, H_2S, CHCl_3 \) and \( NH_3 \) is
- Choose the INCORRECT pair of MOLECULE and its SHAPE among the following:
- Total number of electrons present around the central atom in order of \( \text{PCl}_5 \), \( \text{SF}_6 \), \( \text{SCl}_2 \)
- Which has minimum bond angle?
- A neutral molecule \(XF_{3}\) has a zero dipole moment. The element X is most likely:
View More Questions
Top KEAM Questions
- i.$\quad$ They help in respiration ii.$\quad$ They help in cell wall formation iii.$\quad$ They help in DNA replication iv. $\quad$They increase surface area of plasma membrane Which of the following prokaryotic structures has all the above roles?
- A body oscillates with SHM according to the equation (in SI units), $x = 5 cos \left(2\pi t +\frac{\pi}{4}\right) .$ Its instantaneous displacement at $t = 1$ second is
- The pH of a solution obtained by mixing 60 mL of 0.1 M BaOH solution at 40m of 0.15m HCI solution is
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
- If $\int e^{2x}f' \left(x\right)dx =g \left(x\right)$, then $ \int\left(e^{2x}f\left(x\right) + e^{2x} f' \left(x\right)\right)dx =$
View More Questions