Question:
Which one of the following is an EXCEPTION to the generalization made by Mendel on the basis of his experiments on garden pea plant?
Which one of the following is an EXCEPTION to the generalization made by Mendel on the basis of his experiments on garden pea plant?
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Monohybrid cross:
Genotype = 1:2:1
Phenotype = 3:1 Never the same!
Phenotype = 3:1 Never the same!
Updated On: May 8, 2026
- Single trait $\rightarrow$ single gene $\rightarrow$ Two alleles.
- Two alleles show interaction in which one is completely dominant.
- The genotypic and phenotypic ratios are identical in monohybrid crosses.
- Factors (genes) for different traits present on different chromosomes assort independently.
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The Correct Option is C
Solution and Explanation
Concept: Mendel's laws include:
• Law of dominance
• Law of segregation
• Law of independent assortment In a monohybrid cross:
• Genotypic ratio = $1:2:1$
• Phenotypic ratio = $3:1$ These ratios are not identical.
Step 1: Evaluate each statement.
• (A) True for Mendelian traits
• (B) True (complete dominance assumed)
• (C) False — ratios differ (exception)
• (D) True for independently assorting genes
Step 2: Identify exception.
Only option (C) contradicts Mendel's findings.
Step 3: Conclusion.
Thus, option (C) is the exception. Final Answer: Option (C)
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