Question:
Which one of the following graph represents the correct variation of inductive reactance (\(X_{L}\)) with angular frequency (\(\omega\))?
Which one of the following graph represents the correct variation of inductive reactance (\(X_{L}\)) with angular frequency (\(\omega\))?
Show Hint
Inductive reactance is the product of inductance and angular frequency, so its graph is a straight line through the origin.
Updated On: Nov 12, 2026
- A
- B
- C
- D
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
The inductive reactance is \(X_{L}=\omega L\).
Step 2: Shape of the Graph
For a fixed inductor, \(L\) is constant, so \(X_{L}\propto\omega\). This is a straight line through the origin with positive slope \(L\).
Step 3: Compare the options
Graph (A) is constant, (C) is vertical, and (D) falls with \(\omega\). Graph (B) is the rising straight line from the origin.
Final Answer:
Graph B, a straight line through the origin, is correct. \[ \boxed{\text{(B) }\text{B}} \]
The inductive reactance is \(X_{L}=\omega L\).
Step 2: Shape of the Graph
For a fixed inductor, \(L\) is constant, so \(X_{L}\propto\omega\). This is a straight line through the origin with positive slope \(L\).
Step 3: Compare the options
Graph (A) is constant, (C) is vertical, and (D) falls with \(\omega\). Graph (B) is the rising straight line from the origin.
Final Answer:
Graph B, a straight line through the origin, is correct. \[ \boxed{\text{(B) }\text{B}} \]
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