Question:
Which one of the following compounds undergoes HVZ reaction?
Which one of the following compounds undergoes HVZ reaction?
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The HVZ reaction is characteristic of carboxylic acids, particularly for halogenation followed by decarboxylation.
Updated On: Apr 28, 2026
- \( \text{C}_6\text{H}_5\text{COOH} \)
- \( \text{CH}_3\text{CH}_2\text{COOH} \)
- \( \text{CCl}_3\text{COOH} \)
- \( \text{CH}_3\text{CH}_2\text{CHO} \)
- \( \text{HCOOH} \)
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The Correct Option is B
Solution and Explanation
Step 1: Understand the HVZ reaction.
The HVZ (Hunsdiecker-Von Zamboni) reaction involves the halogenation of carboxylic acids. It typically requires the use of halogens like \( \text{Br}_2 \) or \( \text{Cl}_2 \). The reaction is used for decarboxylation and halogenation of carboxylic acids.
Step 2: Identify the compounds.
The reaction occurs with carboxylic acids. Let's check the compounds in the options: - Option (1): \( \text{C}_6\text{H}_5\text{COOH} \) is benzoic acid, which can undergo the HVZ reaction. - Option (2): \( \text{CH}_3\text{CH}_2\text{COOH} \) is acetic acid, which undergoes the HVZ reaction. - Option (3): \( \text{CCl}_3\text{COOH} \) is trichloroacetic acid, which can also undergo the HVZ reaction. - Option (4): \( \text{CH}_3\text{CH}_2\text{CHO} \) is an aldehyde, which does not undergo the HVZ reaction. - Option (5): \( \text{HCOOH} \) is formic acid, which also undergoes the HVZ reaction.
Step 3: Final conclusion.
Out of the listed options, the correct choice for HVZ reaction is \( \text{CH}_3\text{CH}_2\text{COOH} \), which undergoes halogenation. Therefore, the correct answer is: \[ \boxed{(2)\ \text{CH}_3\text{CH}_2\text{COOH}} \]
The HVZ (Hunsdiecker-Von Zamboni) reaction involves the halogenation of carboxylic acids. It typically requires the use of halogens like \( \text{Br}_2 \) or \( \text{Cl}_2 \). The reaction is used for decarboxylation and halogenation of carboxylic acids.
Step 2: Identify the compounds.
The reaction occurs with carboxylic acids. Let's check the compounds in the options: - Option (1): \( \text{C}_6\text{H}_5\text{COOH} \) is benzoic acid, which can undergo the HVZ reaction. - Option (2): \( \text{CH}_3\text{CH}_2\text{COOH} \) is acetic acid, which undergoes the HVZ reaction. - Option (3): \( \text{CCl}_3\text{COOH} \) is trichloroacetic acid, which can also undergo the HVZ reaction. - Option (4): \( \text{CH}_3\text{CH}_2\text{CHO} \) is an aldehyde, which does not undergo the HVZ reaction. - Option (5): \( \text{HCOOH} \) is formic acid, which also undergoes the HVZ reaction.
Step 3: Final conclusion.
Out of the listed options, the correct choice for HVZ reaction is \( \text{CH}_3\text{CH}_2\text{COOH} \), which undergoes halogenation. Therefore, the correct answer is: \[ \boxed{(2)\ \text{CH}_3\text{CH}_2\text{COOH}} \]
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