Step 1: Understanding the Concept
For a first-order reaction, \(k = \dfrac{2.303}{t}\log\dfrac{[R]_0}{[R]}\).
Step 2: Half-life
Put \([R] = \dfrac{[R]_0}{2}\) and \(t = t_{1/2}\). This gives \(t_{1/2} = \dfrac{0.693}{k}\).
Step 3: Conclusion
The initial concentration \([R]_0\) does not appear, so the half-life is independent of the initial concentration.
Final Answer:
The half-life of a first-order reaction does not depend on the initial concentration.
\[ \boxed{\text{(B) }\text{It is independent of the initial concentration of reactants}} \]