Question:
Which of the following will show geometrical isomerism?
Which of the following will show geometrical isomerism?
Show Hint
For geometrical isomerism, each carbon of the double bond must have two different substituents (abC=Ccd). If any carbon has two identical groups, geometrical isomerism is not possible.
Updated On: May 2, 2026
- 1-butene
- 1,2-dibromobutene
- Propene
- iso-butylene
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Geometrical isomerism (cis-trans) occurs in compounds with restricted rotation, typically due to a double bond, where each carbon of the double bond has two different substituents.
Step 2: Detailed Explanation:
\begin{itemize} \item (A) 1-butene: CH\(_2\)=CH-CH\(_2\)CH\(_3\). One carbon of the double bond has two H atoms, so no geometrical isomerism. \item (B) 1,2-dibromobutene: Br-CH=CBr-CH\(_2\)CH\(_3\). Both carbons of the double bond have different substituents (H and Br on one, Br and CH\(_2\)CH\(_3\) on the other), so it shows cis-trans isomerism. \item (C) Propene: CH\(_3\)-CH=CH\(_2\). One carbon has two H atoms, so no geometrical isomerism. \item (D) iso-butylene: (CH\(_3\))\(_2\)C=CH\(_2\). One carbon has two CH\(_3\) groups, the other has two H atoms, so no geometrical isomerism. \end{itemize}
Step 3: Final Answer:
1,2-dibromobutene shows geometrical isomerism, option (B).
Geometrical isomerism (cis-trans) occurs in compounds with restricted rotation, typically due to a double bond, where each carbon of the double bond has two different substituents.
Step 2: Detailed Explanation:
\begin{itemize} \item (A) 1-butene: CH\(_2\)=CH-CH\(_2\)CH\(_3\). One carbon of the double bond has two H atoms, so no geometrical isomerism. \item (B) 1,2-dibromobutene: Br-CH=CBr-CH\(_2\)CH\(_3\). Both carbons of the double bond have different substituents (H and Br on one, Br and CH\(_2\)CH\(_3\) on the other), so it shows cis-trans isomerism. \item (C) Propene: CH\(_3\)-CH=CH\(_2\). One carbon has two H atoms, so no geometrical isomerism. \item (D) iso-butylene: (CH\(_3\))\(_2\)C=CH\(_2\). One carbon has two CH\(_3\) groups, the other has two H atoms, so no geometrical isomerism. \end{itemize}
Step 3: Final Answer:
1,2-dibromobutene shows geometrical isomerism, option (B).
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