In Kolbe's electrolytic method, fatty acids undergo decarboxylation at the anode, leading to the formation of alkane radicals. The acetate ion does not accept electrons to form a free radical, so statement (D) is incorrect.
Thus, the correct answer is (D).
The vapour pressure of H\(_2\)O at 323K is 95 mm of Hg. 176g of sucrose (Molar mass = 342 gmol\(^{-1}\)) is added to 900g of H\(_2\)O at 323K.
The vapour pressure of solution is about
Kepler's second law (law of areas) of planetary motion leads to law of conservation of