Step 1: Understanding the Concept
Paramagnetism needs at least one unpaired electron in the molecular orbital configuration.
Step 2: Check each species
\(\text{Li}_2\) (6 electrons), \(\text{N}_2\) (14 electrons) and \(\text{F}_2\) (18 electrons) have all electrons paired, so they are diamagnetic.
Step 3: The cation
\(\text{N}_2^{+}\) has 13 electrons. Removing one electron from \(\sigma 2p_z\) of \(\text{N}_2\) leaves one unpaired electron, so it is paramagnetic.
Final Answer:
N2+ is the paramagnetic species.
\[ \boxed{\text{(D) }\text{N}_{2}^{+}} \]