Step 1: Understanding the Concept:
The van't Hoff factor is \(i = \dfrac{\text{normal (theoretical) molar mass}}{\text{observed molar mass}}\). So the question asks for a solute with \(i = 3\).
Step 2: Complete dissociation:
For complete dissociation, \(i\) equals the number of ions per formula unit.
Step 3: Count ions:
KCl gives 2 ions (\(K^+\), \(Cl^-\)), so \(i = 2\).
\(K_2SO_4\) gives \(2K^+ + SO_4^{2-}\), which is 3 ions, so \(i = 3\).
\(MgSO_4\) gives 2 ions, so \(i=2\).
\(Al_2(SO_4)_3\) gives \(2Al^{3+} + 3SO_4^{2-}\), which is 5 ions, so \(i=5\).
Step 4: Select:
Only \(K_2SO_4\) has \(i=3\), option (B).
Final Answer:
K2SO4 gives three ions, so the ratio is 3.
\[ \boxed{B:\ \text{K}_2\text{SO}_4} \]