Question

Which of the following sets of ligands does NOT contain ambident ligand in it?

• A. Oxalate ion, \(\text{NO}_2^-\), \(\text{NCS}^-\)
• B. \(\text{C}_2\text{O}_4^{2-}\), Ethylene diamine, \(\text{H}_2\text{O}\)
• C. \(\text{NO}_2^-\), \(\text{C}_2\text{O}_4^{2-}\), \(\text{EDTA}^{4-}\)
• D. \(\text{EDTA}^{4-}\), \(\text{NCS}^-\), Oxalate ion

Hint:

Ambident ligands include NO2- and NCS-; oxalate, en, water and EDTA are not ambident.

Answer 1

The Correct Option is B

Step 1: Understanding the Concept:
An ambident ligand has two different possible donor atoms. Common examples are \(\text{NO}_2^-\) (N or O) and \(\text{SCN}^-\)/\(\text{NCS}^-\) (S or N).

Step 2: Check option A:
It contains \(\text{NO}_2^-\) and \(\text{NCS}^-\), which are ambident. So A has ambident ligands.

Step 3: Check option B:
Oxalate is a bidentate ligand with two equivalent O donors. Ethylenediamine has two equivalent N donors. Water has one O donor. None is ambident, so B has no ambident ligand.

Step 4: Check options C and D:
C contains \(\text{NO}_2^-\), which is ambident. D contains \(\text{NCS}^-\), which is ambident.

Step 5: Conclusion:
Only option B has no ambident ligand.

Final Answer:
Only set B has no ambident ligand. \[ \boxed{\text{(B) }\text{C}_2\text{O}_4^{2-}\text{, ethylene diamine, H}_2\text{O}} \]