Question:

Which of the following set of compounds does not follow octet rule?}

Show Hint

Common expanded octet examples: \[ PF_5,\ SF_6,\ PCl_5,\ H_2SO_4 \] These usually involve elements from the third period or beyond.
Updated On: Apr 24, 2026
  • \(SCl_2, PF_5\) and \(SF_6\)
  • \(CH_4, PF_5\) and \(SF_6\)
  • \(PF_5, H_2SO_4\) and \(SF_6\)
  • \(PF_5, H_2SO_4\) and \(SCl_2\)
  • \(SCl_2, H_2SO_4\) and \(SF_6\)
Show Solution
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The Correct Option is C

Solution and Explanation

Compounds that do not follow octet rule generally show expanded octet. Check each important compound:
  • \(PF_5\): phosphorus has 10 electrons around it.
  • \(SF_6\): sulfur has 12 electrons around it.
  • \(H_2SO_4\): sulfur shows expanded valency in the usual Lewis description.
But \(CH_4\) follows octet rule, and \(SCl_2\) can be represented with sulfur completing octet. Therefore, the set in which all given compounds do not follow octet rule is: \[ PF_5,\ H_2SO_4,\ SF_6 \]
Hence, the correct answer is: \[ \boxed{(C)} \]
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