Step 1: Understanding the Concept
The first law is \(\Delta U=q+w\). If all heat absorbed is used for work, then \(\Delta U=0\).
Step 2: Which Process Has Zero Internal Energy Change
For an ideal gas, \(\Delta U\) depends only on temperature, so \(\Delta U=0\) when temperature is constant.
Step 3: Compare the options
An isothermal process gives \(q=-w\), so the entire heat absorbed becomes work done by the system. This is option (B).
Adiabatic has \(q=0\), isochoric has \(w=0\), and isobaric changes the internal energy.
Final Answer:
In an isothermal process all the heat absorbed is converted into work.
\[ \boxed{\text{(B) }\text{Isothermal}} \]