Question:
Which of the following pairs of complexes will show approximately the same electrical conductance for their 0.001 M aqueous solutions?
Which of the following pairs of complexes will show approximately the same electrical conductance for their 0.001 M aqueous solutions?
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Which of the following pairs of complexes will show approximately the same electrical conductance for their 0.001 M aqueous solutions?
Updated On: Apr 15, 2026
- $CoCl_{3} \cdot 4NH_{3}$ and $PtCl_{4} \cdot 4NH_{3}$
- $CoCl_{3} \cdot 3NH_{3}$ and $PtCl_{4} \cdot 5NH_{3}$
- $CoCl_{3} \cdot 6NH_{3}$ and $PtCl_{4} \cdot 5NH_{3}$
- $CoCl_{3} \cdot 6NH_{3}$ and $PtCl_{4} \cdot 3NH_{3}$
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The Correct Option is C
Solution and Explanation
Step 1: Concept
Electrical conductance depends on the number of ions produced in solution.
Step 2: Analysis
$CoCl_{3} \cdot 6NH_{3}$ is $[Co(NH_{3})_{6}]Cl_{3}$, which produces 4 ions: $[Co(NH_{3})_{6}]^{3+} + 3Cl^{-}$.
Step 3: Analysis
$PtCl_{4} \cdot 5NH_{3}$ is $[PtCl(NH_{3})_{5}]Cl_{3}$, which also produces 4 ions: $[PtCl(NH_{3})_{5}]^{3+} + 3Cl^{-}$.
Step 4: Conclusion
Since they produce the same number of ionic species, their conductance will be approximately the same.
Final Answer: (C)
Electrical conductance depends on the number of ions produced in solution.
Step 2: Analysis
$CoCl_{3} \cdot 6NH_{3}$ is $[Co(NH_{3})_{6}]Cl_{3}$, which produces 4 ions: $[Co(NH_{3})_{6}]^{3+} + 3Cl^{-}$.
Step 3: Analysis
$PtCl_{4} \cdot 5NH_{3}$ is $[PtCl(NH_{3})_{5}]Cl_{3}$, which also produces 4 ions: $[PtCl(NH_{3})_{5}]^{3+} + 3Cl^{-}$.
Step 4: Conclusion
Since they produce the same number of ionic species, their conductance will be approximately the same.
Final Answer: (C)
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