Question

Which of the following molecules have $\mathrm{dsp}^{2}$ hybridisation?
(i) $[Ni(CN)_4]^{2-}$
(ii) $BrF_5$
(iii) $[Co(NH_3)_6]^{3+}$
(iv) $[CrF_6]^{3-}$
(v) $[PtCl_4]^{2-}$

• A. (i) and (ii)
• B. (i) and (iii)
• C. (ii) and (iii)
• D. (i) and (v)
• E. (iii) and (v)

Hint:

\(dsp^2\) uses inner d-orbitals (3d for first transition series) and is found in square planar complexes with strong field ligands like CN\(^-\), CO, PR\(_3\).

Answer 1

The Correct Option is D

Step 1: Understanding the Concept:
\(dsp^2\) hybridization is square planar, typically for Ni(II), Pt(II), Pd(II) complexes with strong field ligands.

Step 2: Detailed Explanation:}
(i) \([Ni(CN)_4]^{2-}\): Ni\(^{2+}\) (3d\(^8\)), CN\(^-\) strong field, \(dsp^2\) square planar.
(v) \([Pt(Cl)_4]^{2-}\): Pt\(^{2+}\) (5d\(^8\)), \(dsp^2\) square planar.
(ii) \(BrF_5\): \(sp^3d^2\) (octahedral, one lone pair).
(iii) \([Co(NH_3)_6]^{3+}\): \(sp^3d^2\) (octahedral).
(iv) \([CrF_6]^{3-}\): \(sp^3d^2\) (octahedral).

Step 3: Final Answer:}
The complexes with \(dsp^2\) hybridization are (i) and (v).