Question:
Which of the following molecules has a regular geometry as expected?
Which of the following molecules has a regular geometry as expected?
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Regular geometry = All identical surrounding atoms + Zero lone pairs on central atom.
Updated On: May 14, 2026
- $\text{SiCl}_4$
- $\text{SF}_4$
- $\text{BrF}_5$
- $\text{XeF}_4$
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The Correct Option is A
Solution and Explanation
Step 1: Concept According to VSEPR theory, a molecule has regular geometry if the central atom has only bond pairs and no lone pairs of electrons.
Step 2: Meaning Regular geometry implies that the bond angles and shapes are undistorted.
Step 3: Analysis $SiCl_4$ has $sp^3$ hybridization with 4 bond pairs and 0 lone pairs (Tetrahedral). $SF_4$, $BrF_5$, and $XeF_4$ all have lone pairs on the central atom.
Step 4: Conclusion $SiCl_4$ maintains a regular tetrahedral geometry. Final Answer: (A)
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