Question:

Which of the following molecules consist minimum lone pair of electrons in the valence shell of central atom?

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Count the lone pairs on the central atom of each molecule from its valence electrons and bonds.
Updated On: Nov 13, 2026
  • \(\mathrm{SCl}_{2}\)
  • \(\mathrm{PCl}_{3}\)
  • \(\mathrm{ClF}_{3}\)
  • \(\mathrm{XeF}_{4}\)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept
Lone pairs on the central atom = (valence electrons - bonds used)/2.

Step 2: Count
\(\text{SCl}_2\): S has 2 lone pairs. \(\text{PCl}_3\): P has 1 lone pair.

Step 3: More counts
\(\text{ClF}_3\): Cl has 2 lone pairs. \(\text{XeF}_4\): Xe has 2 lone pairs.

Step 4: Result
The minimum is 1 lone pair, in \(\text{PCl}_3\).

Final Answer:
\(\text{PCl}_3\) has the fewest lone pairs on its central atom. \[ \boxed{\text{(B) }\mathrm{PCl}_{3}} \]
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