Step 1: Recall the concept of dipole moment.
Dipole moment is a measure of the separation of positive and negative charges in a molecule. It depends on both bond polarity and molecular geometry. For a molecule to have zero dipole moment, the vector sum of all bond dipoles must cancel out.
Step 2: Analyze the geometry of \(BF_3\).
\(BF_3\) has a trigonal planar geometry with bond angles of \(120^\circ\). The three \(B-F\) bonds are identical and symmetrically arranged in a plane.
Step 3: Check dipole cancellation in \(BF_3\).
Each \(B-F\) bond is polar, but due to perfect symmetry, the dipole moments cancel each other out. Therefore, the net dipole moment is zero.
Step 4: Analyze \(CH_2Cl_2\).
This molecule has a tetrahedral shape, but the substituents are not identical (H and Cl). Hence, dipoles do not cancel, and it has a non-zero dipole moment.
Step 5: Analyze \(NH_3\), \(SO_2\), and \(NF_3\).
\(NH_3\) has a trigonal pyramidal shape, \(SO_2\) is bent, and \(NF_3\) is also trigonal pyramidal. All these geometries are asymmetrical, so they have non-zero dipole moments.
Step 6: Identify the only symmetric molecule.
Among the given options, only \(BF_3\) has perfect symmetry leading to complete cancellation of dipole moments.
Step 7: State the final answer.
Thus, the molecule with zero dipole moment is:
\[
\boxed{BF_3}
\]
which matches option \((1)\).