Question:
Which of the following molecule has tetrahedral geometry?
Which of the following molecule has tetrahedral geometry?
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If central atom has 4 bond pairs and 0 lone pairs, geometry is always tetrahedral.
Updated On: Apr 24, 2026
- \(SF_6\)
- \(PCl_5\)
- \(BF_3\)
- \(BeCl_2\)
- \(NH_4^+\)
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The Correct Option is
Solution and Explanation
Concept:
According to VSEPR theory, molecular geometry depends on the number of bond pairs and lone pairs around the central atom.
Step 1: Analyze each molecule.
• \(SF_6\): Octahedral geometry
• \(PCl_5\): Trigonal bipyramidal
• \(BF_3\): Trigonal planar
• \(BeCl_2\): Linear
• \(NH_4^+\): 4 bond pairs, no lone pairs $\rightarrow$ Tetrahedral
Step 2: Select correct option.
Only \(NH_4^+\) has tetrahedral geometry.
Step 1: Analyze each molecule.
• \(SF_6\): Octahedral geometry
• \(PCl_5\): Trigonal bipyramidal
• \(BF_3\): Trigonal planar
• \(BeCl_2\): Linear
• \(NH_4^+\): 4 bond pairs, no lone pairs $\rightarrow$ Tetrahedral
Step 2: Select correct option.
Only \(NH_4^+\) has tetrahedral geometry.
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