Question:
Which of the following molecule has double bond with two $\pi$ bonds?
Which of the following molecule has double bond with two $\pi$ bonds?
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$C_2$ is a special case in MO theory where the double bond is considered to contain two $\pi$ bonds.
Updated On: Apr 24, 2026
- $Ne_2$
- $O_2$
- $B_2$
- $C_2$
- $Li_2$
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The Correct Option is D
Solution and Explanation
Concept:
Chemistry - Molecular Orbital Theory.
Step 1: Check bond type in each molecule. * $Li_2$ has single $\sigma$ bond. * $B_2$ has bond order 1. * $O_2$ has one $\sigma$ and one $\pi$ bond. * $Ne_2$ is unstable. * $C_2$ has bond order 2.
Step 2: Bonding in $C_2$. For $C_2$, molecular orbital configuration shows two $\pi$ bonds and no net $\sigma(2p)$ bond. Thus it behaves as a double bond made of: [ \pi + \pi ]
Step 3: Final answer. [ \boxed{C_2} ]
Hence, correct option is (D).
Step 1: Check bond type in each molecule. * $Li_2$ has single $\sigma$ bond. * $B_2$ has bond order 1. * $O_2$ has one $\sigma$ and one $\pi$ bond. * $Ne_2$ is unstable. * $C_2$ has bond order 2.
Step 2: Bonding in $C_2$. For $C_2$, molecular orbital configuration shows two $\pi$ bonds and no net $\sigma(2p)$ bond. Thus it behaves as a double bond made of: [ \pi + \pi ]
Step 3: Final answer. [ \boxed{C_2} ]
Hence, correct option is (D).
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