Question:
Which of the following metals does not form \(\text{MH}_{2}\) type hydride when heated with hydrogen under normal conditions?
Which of the following metals does not form \(\text{MH}_{2}\) type hydride when heated with hydrogen under normal conditions?
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Beryllium hydride cannot be made by direct combination of the metal with hydrogen.
Updated On: Nov 12, 2026
- Be
- Mg
- Ca
- Sr
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
Group 2 metals combine with dihydrogen on heating to give hydrides of the type \(\text{MH}_2\).
Step 2: Exception
Beryllium does not react directly with hydrogen. \(\text{BeH}_2\) is made indirectly by reducing \(\text{BeCl}_2\) with \(\text{LiAlH}_4\).
Step 3: Compare the options
Mg, Ca and Sr form \(\text{MH}_2\) on heating with hydrogen, so Be is the answer, option (A).
Final Answer:
Beryllium does not form its hydride by direct heating with hydrogen. \[ \boxed{\text{(A) }\text{Be}} \]
Group 2 metals combine with dihydrogen on heating to give hydrides of the type \(\text{MH}_2\).
Step 2: Exception
Beryllium does not react directly with hydrogen. \(\text{BeH}_2\) is made indirectly by reducing \(\text{BeCl}_2\) with \(\text{LiAlH}_4\).
Step 3: Compare the options
Mg, Ca and Sr form \(\text{MH}_2\) on heating with hydrogen, so Be is the answer, option (A).
Final Answer:
Beryllium does not form its hydride by direct heating with hydrogen. \[ \boxed{\text{(A) }\text{Be}} \]
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