Question:

Which of the following metacestode gives rise to a maximum number of tapeworms when ingested by the definitive host?
A. Coenurus
B. Cysticercus
C. Plerocercoid
D. Hydatid

Show Hint

Remember the scaling of asexual reproduction in larval tapeworms:
- Cysticercus/Plerocercoid = 1 scolex (1 adult worm)
- Coenurus = Multiple scolices (hundreds of adult worms)
- Hydatid = Brood capsules with massive multiplication (millions of adult worms)
  • Coenurus
  • Cysticercus
  • Plerocercoid
  • Hydatid
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Metacestodes can be categorized structurally based on their budding capability and the number of future scolices (heads) they contain.
When an intermediate host harboring metacestodes is eaten by a definitive host, each viable scolex present in the metacestode can attach to the intestinal wall and develop into one adult tapeworm.

Step 2: Detailed Explanation:

Let us compare the potential of each metacestode type to yield adult tapeworms:
- Cysticercus: This larval stage possesses a single invaginated scolex.
Ingesting one cysticercus results in the development of exactly one adult tapeworm.
- Plerocercoid: This is an unsegmented, solid larval stage of pseudophyllidean tapeworms (e.g., Diphyllobothrium) possessing a single scolex.
It yields exactly one adult tapeworm.
- Coenurus: This is a fluid-filled bladder containing multiple scolices (typically tens to a few hundred) budding from the internal germinal membrane.
Ingesting one coenurus can yield a few hundred adult tapeworms.
- Hydatid cyst: This larval stage of Echinococcus species undergoes extensive asexual reproduction.
The germinal layer buds off thousands of brood capsules, each containing multiple protoscolices.
A single large hydatid cyst can harbor millions of viable protoscolices.
Ingestion of a single hydatid cyst can therefore result in the development of thousands to millions of adult tapeworms in the small intestine of the definitive host.

Step 3: Final Answer:

The hydatid cyst contains the highest number of potential scolices, giving rise to the maximum number of adult tapeworms.
Therefore, the correct option is (D).
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