Question:
Which of the following ligands splits d orbitals to maximum level?
Which of the following ligands splits d orbitals to maximum level?
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Cyanide is at the strong field end of the spectrochemical series.
Updated On: Oct 1, 2026
- \(\text{CN}^-\)
- \(\text{H}_2\text{O}\)
- \(\text{Cl}^-\)
- \(\text{NH}_3\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
The spectrochemical series arranges ligands by the crystal field splitting they cause. Strong field ligands give a large \(\Delta_o\).
Step 2: Detailed Explanation
The series runs: \(\text{I}^- < \text{Br}^- < \text{Cl}^- < \text{F}^- < \text{H}_2\text{O} < \text{NH}_3 < \text{en} < \text{CN}^- < \text{CO}\).
Among the options, \(\text{CN}^-\) is the strongest, so it splits the d orbitals the most.
Final Answer:
Cyanide causes the largest splitting, option (A). \[ \boxed{\text{CN}^-} \]
The spectrochemical series arranges ligands by the crystal field splitting they cause. Strong field ligands give a large \(\Delta_o\).
Step 2: Detailed Explanation
The series runs: \(\text{I}^- < \text{Br}^- < \text{Cl}^- < \text{F}^- < \text{H}_2\text{O} < \text{NH}_3 < \text{en} < \text{CN}^- < \text{CO}\).
Among the options, \(\text{CN}^-\) is the strongest, so it splits the d orbitals the most.
Final Answer:
Cyanide causes the largest splitting, option (A). \[ \boxed{\text{CN}^-} \]
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