Step 1: Understanding the Concept
For a zero order reaction the rate does not depend on concentration, so the reactant is used up at a constant rate.
Step 2: Integrated equation
\([A]_t=[A]_0-kt\)
Step 3: Half life
At \(t=t_{1/2}\), \([A]_t=\dfrac{[A]_0}{2}\). So \(\dfrac{[A]_0}{2}=kt_{1/2}\), which gives \(t_{1/2}=\dfrac{[A]_0}{2k}\).
Step 4: Compare the options
Since \(t_{1/2}\propto[A]_0\), the half life is directly proportional to the initial concentration of the reactant.
Final Answer:
The half life is directly proportional to the initial concentration of the reactant.
\[ \boxed{\text{(A) }\text{It is directly proportional to initial concentration of reactants}} \]