Question:
Which of the following is the correct decreasing order of oxidizing power of perhalate ions?
Which of the following is the correct decreasing order of oxidizing power of perhalate ions?
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Perbromate is the strongest oxidiser among perhalates because of the poor stability of Br in the +7 state.
Updated On: Oct 1, 2026
- \(\text{BrO}_4^- < \text{IO}_4^- < \text{ClO}_4^-\)
- \(\text{IO}_4^- > \text{BrO}_4^- > \text{ClO}_4^-\)
- \(\text{IO}_4^- < \text{BrO}_4^- < \text{ClO}_4^-\)
- \(\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
The oxidising power of perhalate ions \(\text{XO}_4^-\) (halogen in +7) depends on how readily the +7 state is reduced.
Step 2: Detailed Explanation:
Bromine in +7 state is unusually unstable because of the poor shielding by the filled 3d electrons (the d-block contraction). So \(\text{BrO}_4^-\) is the strongest oxidising agent.
Iodine in +7 is more stable due to its larger size, and chlorine in +7 is kinetically slow to react. So \(\text{ClO}_4^-\) is the weakest oxidiser of the three.
Order: \(\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-\).
Step 3: Check the options.
(A) and (C) put \(\text{ClO}_4^-\) as the strongest, which is incorrect. (B) puts \(\text{IO}_4^-\) first and is incorrect. Only (D) matches.
Final Answer:
The decreasing order is \(\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-\), option (D). \[ \boxed{\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-} \]
The oxidising power of perhalate ions \(\text{XO}_4^-\) (halogen in +7) depends on how readily the +7 state is reduced.
Step 2: Detailed Explanation:
Bromine in +7 state is unusually unstable because of the poor shielding by the filled 3d electrons (the d-block contraction). So \(\text{BrO}_4^-\) is the strongest oxidising agent.
Iodine in +7 is more stable due to its larger size, and chlorine in +7 is kinetically slow to react. So \(\text{ClO}_4^-\) is the weakest oxidiser of the three.
Order: \(\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-\).
Step 3: Check the options.
(A) and (C) put \(\text{ClO}_4^-\) as the strongest, which is incorrect. (B) puts \(\text{IO}_4^-\) first and is incorrect. Only (D) matches.
Final Answer:
The decreasing order is \(\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-\), option (D). \[ \boxed{\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-} \]
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